39 lines
1.4 KiB
Diff
39 lines
1.4 KiB
Diff
The compileall script is used to compile to python bytecode all the modules.
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However, it relies on the struct package that is not built for the host
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python, thus crashing at execution when compiling the target python.
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When compiling, the removed code block is never executed, so we can safely
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remove it, removing in the same time the dependency on struct.
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Patch by Maxime Ripard <ripard@archos.com>
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Index: Python-2.7/Lib/compileall.py
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===================================================================
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--- Python-2.7.orig/Lib/compileall.py (révision 84276)
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+++ Python-2.7/Lib/compileall.py (copie de travail)
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@@ -14,7 +14,6 @@
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import os
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import sys
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import py_compile
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-import struct
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import imp
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__all__ = ["compile_dir","compile_file","compile_path"]
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@@ -83,17 +82,6 @@
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if os.path.isfile(fullname):
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head, tail = name[:-3], name[-3:]
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if tail == '.py':
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- if not force:
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- try:
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- mtime = int(os.stat(fullname).st_mtime)
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- expect = struct.pack('<4sl', imp.get_magic(), mtime)
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- cfile = fullname + (__debug__ and 'c' or 'o')
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- with open(cfile, 'rb') as chandle:
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- actual = chandle.read(8)
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- if expect == actual:
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- return success
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- except IOError:
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- pass
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if not quiet:
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print 'Compiling', fullname, '...'
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try:
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