package/libxml-parser-perl: use the compiler as "LD"
Since commit efa95b19ae
("package/libxml-parser-perl: make host build use correct compiler"),
we pass $(HOST_CONFIGURE_OPTS) when building host-libxml-parser-perl,
in order to use the correct host compiler.
However, this means that LD="$(HOSTLD)" is passed. However, the
host-libxml-parser-perl passes compiler arguments to LD, so it really
assumes that LD is gcc, not ld. For example, it tries to pass
-mtune=generic.
So, let's tell host-libxml-parser-perl that LD is "$(HOSTCC)".
Fixes:
http://autobuild.buildroot.net/results/2ed2e5ccefe9047c597f84d5880de2e8de2bdd94/
Signed-off-by: Thomas Petazzoni <thomas.petazzoni@bootlin.com>
Tested-by: Joseph Kogut <joseph.kogut@gmail.com>
Signed-off-by: Yann E. MORIN <yann.morin.1998@free.fr>
This commit is contained in:
parent
2134df9de4
commit
43a26d7fe4
@ -12,9 +12,14 @@ LIBXML_PARSER_PERL_LICENSE = Artistic or GPL-1.0+
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LIBXML_PARSER_PERL_LICENSE_FILES = README
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LIBXML_PARSER_PERL_RUN_PERL = `which perl`
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HOST_LIBXML_PARSER_PERL_CONFIGURE_OPTS = \
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$(HOST_CONFIGURE_OPTS) \
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LD="$(HOSTCC)"
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define HOST_LIBXML_PARSER_PERL_CONFIGURE_CMDS
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(cd $(@D) ; \
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$(HOST_CONFIGURE_OPTS) $(LIBXML_PARSER_PERL_RUN_PERL) Makefile.PL \
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$(HOST_LIBXML_PARSER_PERL_CONFIGURE_OPTS) \
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$(LIBXML_PARSER_PERL_RUN_PERL) Makefile.PL \
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PREFIX=$(HOST_DIR) \
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EXPATLIBPATH=$(HOST_DIR)/lib \
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EXPATINCPATH=$(HOST_DIR)/include \
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@ -25,7 +30,7 @@ define HOST_LIBXML_PARSER_PERL_CONFIGURE_CMDS
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endef
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define HOST_LIBXML_PARSER_PERL_BUILD_CMDS
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$(HOST_MAKE_ENV) $(MAKE) $(HOST_CONFIGURE_OPTS) -C $(@D)
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$(HOST_MAKE_ENV) $(MAKE) $(HOST_LIBXML_PARSER_PERL_CONFIGURE_OPTS) -C $(@D)
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endef
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define HOST_LIBXML_PARSER_PERL_INSTALL_CMDS
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