core: remove redundant "override O := $(O)"

The top-level Makefile contains an "override O := $(O)" statement that
is purportedly required to make sure the O flag doesn't leak into the
environment of sub-makes. However, since commit 173135d, there is
already an "override O := ..." a few lines down. Therefore, the first
override is redundant.

Signed-off-by: Arnout Vandecappelle (Essensium/Mind) <arnout@mind.be>
Reviewed-by: Samuel Martin <s.martin49@gmail.com>
Signed-off-by: Thomas Petazzoni <thomas.petazzoni@free-electrons.com>
This commit is contained in:
Arnout Vandecappelle 2016-11-03 02:55:17 +01:00 committed by Thomas Petazzoni
parent 5e3f89666b
commit 2048e22fa1

View File

@ -34,13 +34,6 @@ SHELL := $(shell if [ -x "$$BASH" ]; then echo $$BASH; \
# build by preventing it from being forwarded to sub-make calls.
ifneq ("$(origin O)", "command line")
O := $(CURDIR)/output
else
# Strangely enough O is still passed to submakes with MAKEOVERRIDES
# (with make 3.81 atleast), the only thing that changes is the output
# of the origin function (command line -> environment).
# Unfortunately some packages don't look at origin (E.G. uClibc 0.9.31+)
# To really make O go away, we have to override it.
override O := $(O)
endif
# Check if the current Buildroot execution meets all the pre-requisites.